Webkeep dividing 100 by 2 till you get a value < 2 100 / 2 = 50 50 / 2 = 25 25 / 2 = 12 (forget about the remainder) 12 / 2 = 6 6 / 2 = 3 3 / 2 = 1 now just add up all the quotients 50 + 25 + 12 + 6 + 3 + 1 = 97 the same logic can be applied to find the highest power of any number x that divides n! completely or evenly. Share Cite Follow WebSolution. 120 is a composite number so it has more then two factors unlike a prime number which has only two factors i.e ,1 and the number itself. But 120 can be expressed in terms of its prime factors as 120= 2×2×2×3×5 The above 5 prime factors it has other factors too The same can be calculated by: Numbers of factors=Each prime factors ...
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WebNov 2, 2024 · Answer: Maximum power of 6 in 120! is given by Highest power of 3 in 120! Hence the maximum power of 6 which can divide 120! without leaving a remainder is 58. … WebThere are multiple ways to find the greatest common factor of given integers. One of these involves computing the prime factorizations of each integer, determining which factors they have in common, and multiplying these factors to find the GCD. Refer to the example below. EX: GCF (16, 88, 104) 16 = 2 × 2 × 2 × 2. 88 = 2 × 2 × 2 × 11. john bartelstone photography
What is the highest power of 2 in n!? : Data Sufficiency (DS)
WebApr 4, 2024 · I want to find the highest power of 2 in the list satisfied as. For the first number, the highest power of 2 will get the first element of the list as input. So the result is 16 (closest to 20) For the next numbers, it will get the summation of previous result (i.e 16) and current number (.i.e 40) so the closest number will be 32 (closest 40 +16) WebGiven an integer n, return true if it is a power of two. Otherwise, return false.. An integer n is a power of two, if there exists an integer x such that n == 2 x.. Example 1: Input: n = 1 Output: true Explanation: 2 0 = 1 Example 2: Input: n = 16 Output: true Explanation: 2 4 = 16 Example 3: Input: n = 3 Output: false Constraints:-2 31 <= n <= 2 31 - 1; Follow up: … WebDec 19, 2024 · Prime Factors of 12 are 2 and 3. Your analysis of highest power depends on the larger prime factor is absolutely correct, but in this problem the power of prime factor 2 is 2(i.e \(2^2\) *3=12). So the highest power of 12 depends on the powers of prime factor 2 If the highest power of 12 depends on the power of 3, then the answer will be 31 though. intelligence briefing with steve schultz